Solve the equation xux yuy 0 with the auxiliary condition u
Solve the equation xux +yuy = 0 with the auxiliary condition u(1,x) = x^2
Solution
Solution-
xux + yuy = 0.
By the method of characteristics,
P = x, Q = y , R = 0
1/y dy = 1/x dx and du = 0
log y = logx + c,
log (y/x) = c
or, y = xe^c
or, y/x = K = e^c.
u(x,y) = f(y/x) is general solution.
Application of the boundry conditions u=x^2 on the line y=x and x=1 now determines function f because on y=x
u (1,x) = x^2
f (x) = x^2 means f(t) = t^2
thus, u(x,y) = log (y/x)^2
u(x,y) = 2log (y/x) is the final answer.
