If the hypotenuse of a right triangle is 1 m more than the l

If the hypotenuse of a right triangle is 1 m more than the longer leg, and the shorter leg is 11 m long, find the length of the longer leg. The longer leg is m.

Solution

shorter length = 11m

let the longer length be x

hypotenuse = (x+1)

so, by pythogoras theorem

11^2 +(x)^2 = (x+1)^2

so x=60m

so longer leg = 60m