Let A be a 6 times 4 matrix with linearly independent column
Let A be a 6 times 4 matrix with linearly independent columns. What can we say about Null A?
Solution
A has 6 x4 matrix with linearly independent columns
So, if 4 columns are independent i.e has pivots
Then Null(A) = 6 -4 = 2 --- ( maximum)
If min. A has 2 independent columns ie.e 2 pivots
Then Null(A) = 6- 2 = 4
