Homework SourseFind all relative extrema of the function Use the SecondDeri
Find all relative extrema of the function. Use the Second-Derivative Test when applicable. (If an answer does not exist, enter DNE.) f (x) = x^4 ? 8x^3 + 3 relative minimum (x, y) = ( ) relative maximum (x, y) = ( ) Experts only I will Rate!
Solution
f\'(x) = 4x^3 -24x^2 => f\' = 0 for x = 0 ,6 f\'\'(x)= 12x^2 - 48x for x = 0 we have critical point since f\'\' == 0 f\'\'(6) is neg ==> we have rel min at 6 hence rel max= 0,3 rel min= 6,-429
