Let A be an nn real matrix Show that i detATA 0Solutiongiven

Let A be an n×n real matrix. Show that (i) det(A^TA) 0.

given that A is n,n real matrix

And we know that det (A)=det (A\')

If det (A)>=0

Then det (A\')>=0

which umplies det AA\'>=0

if det A<0 then det A\'<0

Which implies that det(AA\')>0

That is det(AA\')>=0

$Let A be an n×n real matrix. Show that (i) det(A^TA) 0.Solutiongiven that A is n,n real matrix And we know that det (A)=det (A\') If det (A)>=0 Then det (A\'$

Let A be an nn real matrix Show that i detATA 0Solutiongiven

Solution

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