Find the phase the quality x if applicable and the missing p

Find the phase, the quality x if applicable, and the missing property P or T a. H2O at T= 120°C with v 0.5 m/kg b. H2O at P-100 kPa with v 1.8 m/kg C. H2O at T 263 K with v 200 m/kg d. NH3 at P-800 kPa with v = 0.2 m/kg e, NH, at T 20°C with v = 0.1 m3/kg

Solution

a)

Given, Temperature (T) =1200C = 393 K ;

Volume per unit mass (V/m) = 0.5 m3/Kg;

Given substance is H2O i.e. Molecular Mass (M) = 18 g/mol

From Ideal Gas equation PV=nRT;

where, n= m (mass of given substance )/ M (Molecular mass)

Hence PV=nRT can be rearranged as P*(V/m) = RT/M

therefore P= (8.314* 393) / (0.5*18) = 342.87 K Pa;

where R= 8.314 J/mol/K

b)

P= 100 K Pa;

V/m = 1.8 m3/Kg

M = 18 g/mol

R= 8.314 J/mol/K

Substituting all the values in Ideal Gas Equation i.e. PV=nRT

T= (100 KPa* 18 g/mol *1.8 m3/Kg) / (8.314 J/mol/K) = 389.704 K =116.550C

c)

Same as above, substituting all the values in Ideal gas Equation PV=nRT

P=(8.314*263)/(18*200)= 0.6 KPa

d)

Here M= 17;

Substituting given values in PV=nRT;

T= (800kPa*0.2m3/Kg) / (8.314J/mol/K * 17 g/mol) = 1.13 K = (-272.02 0C)

e) substituting given values in Ideal Gas Equation

P= (8.314 J/mol/K * 293K) / (17 g/mol * 0.1 m3/Kg) = 1432.92 KPa

 Find the phase, the quality x if applicable, and the missing property P or T a. H2O at T= 120°C with v 0.5 m/kg b. H2O at P-100 kPa with v 1.8 m/kg C. H2O at T

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