Thermodynamics SolutionFollowing the path shown 123 this is

Solution

Following the path shown,

1-->2--->3

this is the sam e as 1-->3

Assuming no losses, the path 1---> 3 is isothermal at 600C

The associated entropy change is (1.0-0.3) Kj/Kg degK

dQ= T dS by definition,

So dQ = (600+273)*0.7 kJ/Kg= 873*0.7 KJ/Kg

= 611.1 KJ/Kg

By Thermo laws, dQ=dW = 611.1.KJ/Kg