Show that R has 2 1 uncountable dense subsetsSolutionSince i
Show that R has 2^{ 1} uncountable dense subsets
Solution
Since irrationals are uncountable, so their cardinality is 2^N. Set of rationals Q is countable and dense subset of R, so kQ is countable and dense subset of R, where k is irrational number. Therefore number of kQ is uncountable, so cardinality of kQ is 2^N
