In the course of subjecting 100 components to 5000 hours of
Solution
Back-up Theory
Average Failure Rate = 1/Average Life. i.e., if m = average life in, say hours, average failure rate per hour () = 1/m
Now, to calculate m, out of 100, five had a life of 2500 and 95 had a life of 5000. So, m = {(5 x 2500) + (95 x 5000)}/100 = 12500 + 475000)/100 = 487500/100 = 4875 hrs = m
Answer for Part (a)
m = 4875 hours => as against 5000 hours, the average life is only 4875 hours => survival % = 97.5 => failure % = 100 – 97.5 = 2.5% ANSWER
Answer for Part (b)
This is same as average failure rate () = 1/m = 1/4875 = 0.0002 ANSWER
Answer for Part (c)
With a failure rate of 0.0002 per component per hour, (as obtained in (b) above), failure rate per year of 1750 hours of utilization = 1750 x 0.0002 = 0.35 ANSWER
Answer for Part (d)
Expected number of failures of 500 components over one year (next year) = 500 x failure percentage = 500 x 2.5% = 12.5 ANSWER
