How do I rewrite 44x in the form bxSolutionamnamn am1am 44x

How do I rewrite 4^-4x in the form b^x?

a^mn=(a^m)ⁿ ,a^-m=(1_/a^m)

4^-4x

=(4^-4)^x

=(1_/4⁴)^x

=(1_/256)^x

therefore 4^-4x=(1_/256)^x

in this case ,b =(1_/256)

How do I rewrite 4^-4x in the form b^x?Solutionamn=(am)n ,a-m=(1/am) 4-4x =(4-4)x =(1/44)x =(1/256)x therefore 4-4x=(1/256)x in this case ,b =(1/256)

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