S span u v S Let S span u v For each of the following sets
     S = span {u, v}  S  Let S = span {u, v}. For each of the following sets of vectors determine whether S is a line or a plane.  u = [-1  -2  -5], v = [-4  -11  -21],  u = [2  3  2], v = [-4  -6  -4], u = [3  -10  -5], v = [0  0  0], u = [-3  -5  -1], v = [-8  -15  -5]![S = span {u, v} S Let S = span {u, v}. For each of the following sets of vectors determine whether S is a line or a plane. u = [-1 -2 -5], v = [-4 -11 -21], u   S = span {u, v} S Let S = span {u, v}. For each of the following sets of vectors determine whether S is a line or a plane. u = [-1 -2 -5], v = [-4 -11 -21], u](/WebImages/44/s-span-u-v-s-let-s-span-u-v-for-each-of-the-following-sets-1137306-1761609068-0.webp) 
  
  Solution
The set would be a plane if the vectors are linearly independent and a line if they are linearly dependent
For non zero two vectors to be linearly dependent one must be a multiple of the other
1.
Vectors are not multiples of each other hence linearly independent
Hence span S is a plane.
2.
-2u=v
So vectors are linearly dependent. HEnce span S is a line
3.
Second vector is a 0 vector
Hence span S is a line
4.
Vectors are not multiples of each other. Hence Span S is a plane
![S = span {u, v} S Let S = span {u, v}. For each of the following sets of vectors determine whether S is a line or a plane. u = [-1 -2 -5], v = [-4 -11 -21], u   S = span {u, v} S Let S = span {u, v}. For each of the following sets of vectors determine whether S is a line or a plane. u = [-1 -2 -5], v = [-4 -11 -21], u](/WebImages/44/s-span-u-v-s-let-s-span-u-v-for-each-of-the-following-sets-1137306-1761609068-0.webp)
