How do I answer r for figure 4 3 For Figure 3 ground The sup

How do I answer r for figure 4?

3. For Figure 3 ground. The supilot\'s view to the end of the runway (E) is 27°. The plane is 1.4m above the 0.5m above the s rcty above the plane. The eagle is directly below the nose of the plane and is 0.5m above the ground. The angle of depression from the p sion from the pilot\'s view to the beginning of the runway is 409 and the angle How far is the nose of the plane\'s shadow from the beginning of the runway a. b. How long is the runway? c. Length of PE= d. Length of PB e. What is the angle of elevation from the end of the runway (E) to the eagle? Given: Uz Name the following 4. For Figure 4 ZF. DZ = 1.25\".?R = 2\", CS = 7\". DS = 3\".MU = 6\", mzRMU = 45°, a. A chord B b. A diameter AL c. A radius _ d. A secant NX e. A point of tangency C f. A minor arc LG g. A major arc_Ax h. A tangent (non-common) i. A common internal tangent j. A common external tangent T k. Tangent circles Name two arcs that are on separate concentric circles 1. m, AD = P. mCSD q. Area of shaded region (segment QR) r. The figure is a scale model of the Earth OE, where 1\" in the model is 1000 mi in real life The radius of the earth in the model is 4\" and a satellite (S) is above the Earth\'s surface. How far is the satellite from the horizon of the Earth in the model? How far would that be in real life? 5. For Figure 5 Given: m0TW = 200°,IT is a diameter,cr 11 RS Find the area of the shaded region (round to the nearest tenth). Find the arc length of OVW (round to the nearest tenth of a meter) Find the area of sector VCU (round to the nearest tenth) a. c.

Solution

R. As it is mentioned in question the satelite is 0.25\" above the surface of earth or we can say 0.25\" from the horizon as horizon is parallel to the surface of the earth. answer ( 0.25 inch)

Now as mentioned 1 inch is 1000miles so in real life the distance will be 250 miles.