The mechanism below has the velocity at point B vB is given

The mechanism below has the velocity at point B, v_B, is given by the vector shown with the magnitude of 20 m/sec. Noted that the velocity at C (v_C) and the relative velocity of the link BC (v_B/c) are perpendicular to the links CD and BC respectively. Determine v_C knowing v_B = v_C + v_B/C.

Solution

So we have given that,

Velocity at point B, V_b= 20 m/s

Velocity at point C, V_c is perpendicular link CD,

Velocity at point BC, V_b/c is perpendicular to the link BC

So we have given that

V_b=   V_{c +} V_b/c

_{The relative velocity of BC, Vb/c= Vc-Vb}

_{putting this value in above equation, we get}

V_b=   V_{c +} V_c-V_b

So we get

2V_b=2V_c

Ans The velocity at Vector B will be V_b= 20 m/s