Looking for the most elegant way to solve this We are curren
Looking for the \"most elegant\" way to solve this. We are currently working on the law of sines/ law of cosines. Thank you!
 12. A fisherman leaves his home port and heads in the direction N70°W. He travels 30 miles and reaches Egg Island. The next day, he sails N10°E for 50 miles, reaching Forrest Island. What is the distance between the fisherman\'s home port and Forrest Island to the nearest mile? a. he nearest tenth of a degree, what is the bearing from Forrest Island back to his home port? Solution
Here
 90° - 70° = 20 < right triangle North to South & East to West at Home.
 90° - 10° = 80 < right triangle North to South & East to West at Egg. Angle of direction with respect to East West Line
 
 80° + 20° (angle of approach) = 100° This make the Angle of Aproach & Angle of departure.
 Cosine Law
 Distance between Home & Forrest = HF
 HF = [(30)² + (50)² - 2(30)(50) Cos 100°
 HF = (900) + 2500 - 3000 (-0.17)
 HF = (900) + 2500 + 520.95
 ======================
 HF = 62.62 mi  
 ======================
 
 b. Sine Law
 Sin 100° / 62.62 = Sin  / 30
 Sin  = 0.47
  = 28.15°
 Bearing of E (90°-28.15°)S
 ======================================...
 Bearing from Forrest to home = E 61.85° S

