During a rock concert the noise level in decibels in front r

During a rock concert, the noise level (in decibels) in front row seats has a mean of 90 dB with a standard deviation of 7 dB. Without assuming a normal distribution, find the minimum percentage of noise level readings within 16 standard deviations of the mean.

Solution

From Chebyshev\'s theorem, within k standard deviations from the mean is

1 - 1/k^2

as k = 19, then

1 - 1/k^2 = 1 - 1/19^2 = 0.997229917 = 99.723% [ANSWER]