Homework SourseA 150 kg block is attached to a horizontal spring with sprin
A 1.50 kg block is attached to a horizontal spring with spring constant 2150 N/m . The block is at rest on a frictionless surface. A 8.00 g bullet is fired into the block, in the face opposite the spring, and sticks.
Part A
What was the bullet\'s speed if the subsequent oscillations have an amplitude of 16.6 cm ?
A 1.50 kg block is attached to a horizontal spring with spring constant 2150 N/m . The block is at rest on a frictionless surface. A 8.00 g bullet is fired into the block, in the face opposite the spring, and sticks.
Part A
What was the bullet\'s speed if the subsequent oscillations have an amplitude of 16.6 cm ?
A 1.50 kg block is attached to a horizontal spring with spring constant 2150 N/m . The block is at rest on a frictionless surface. A 8.00 g bullet is fired into the block, in the face opposite the spring, and sticks.
Part A
What was the bullet\'s speed if the subsequent oscillations have an amplitude of 16.6 cm ?
Solution
The Kinetic energy K of the bullet block must equal the potential energy U of the spring at max amplitude A
So 1/2(M+ m)*V^2 = 1/2*k*A^2
So V = sqrt(k*A^2/(M + m)) = sqrt(2150*0.166^2/(1.50 + 0.008)) = 6.27 m/s
Now from conservation of momentum \\
m*v = (M + m)*V
so v = (M + m)*V/m = (1.50 + 0.008)*6.27/0.008= 1181.9 m/s
