differential equationsSolutionb According to Eulers method t


differential equations

Solution

b>

According to Eulers method
the approximate value of f at x=a with a step size h is

f(a) = f(a-h) + f\'(a-h)*h

we are given f(0) = 1
=> f\'(x) = 5y-4x
f\'(0) = 5(1) - 4(0) =5

f(.1) = f(0) + f\'(0)*(.1)
      = 1 + 5*.1 = 1.5

=> f(0.2) =f(.1) +f\'(.1)*(.1)

        now when x = .1 , f = 1.5
=> f\'(.1) = 5(1.5) - 4(.1) = 7.1

=> f(0.2) =1.5 + (7.1)*(.1) = 2.21

 differential equationsSolutionb> According to Eulers method the approximate value of f at x=a with a step size h is f(a) = f(a-h) + f\'(a-h)*h we are given

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