Find the equation of the tangent line to the curve y x1x at

Find the equation of the tangent line to the curve
y = x-(1/x) at x = 3/2.


Find the value of x-(1/x) and its derivative at x = 3/2.
f(3/2) =

f \'(3/2) =

Solution

y = x-(1/x)

Slope = dy/dx = 1 - 1/x^2

Therefore

at x = 3/2

dy/dx = 1 - 4/9

= 5/9

f(3/2) = (3/2) - (2/3)

Therefore

Equation

(y - 5/6) = (5/9)(x - 3/2)

Therefore

y = 5x/9

Find the equation of the tangent line to the curve y = x-(1/x) at x = 3/2. Find the value of x-(1/x) and its derivative at x = 3/2. f(3/2) = f \'(3/2) =Solution

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