2 If possible find the exact value of the following a arccos

2. If possible, find the exact value of the following: a. arccos coS a. b. sin (arcsin 3) b. sin arccos- Simplify your answer if necessary.) c,

a) arccos[cos(7/2)] = 7/2

b) sin(arcsin 3) = 3

c) sin[arccos(-5/9)]

cosA = Base/Hyp = 5/9

Perpendicular = (81 - 25) = 214

So, sinA = Perpendicular/Hyp = (214)/9

Hence sin[arccos(-5/9)] = (214)/9