Consider two point charges which are 4cm apart q1 4nC and

Consider two point charges which are 4[cm] apart. q1 = + 4[nC] and q2 = - 4[nC]. a) Along the line that connects the two charges, where is the electric field due to both charges zero? b) What is the potential due to the two charges at the points which are 3 [cm] away from q1 and 5[cm] from q2? c) How much work does it cost to move a -1[nC] point charge between these two points?

Lets assume total electric field will be zero at x distance from q2

E = E1 + E2 = 0

E1 = -E2

k*q1/(d-x)^2 = k*q2/(x)^2

q1/q2 = ((d-x)/x)^2

(d-x)/x = sqrt (q1/q2)

x = d/(sqrt (q1/q2) + 1)

x = 4*10^-2/(sqrt(4/4) + 1)

x = 4*10^-2/(1 + 1)

x = 2*10^-2 m = 2 cm

means at the center of these two charg electric field will be zero.

V = V1 + V2

V = k*q1/r1 + k*q2/r2

V = 9*10^9*4*10^-9/0.03 - 9*10^9*4*10^-9/0.05

V = 480

work is given by

W = q*dV

W = q*potential difference between the center of these charges

W = q*(Vinfinity - Vc)

W = q*(0 - (9*10^9*4*10^-9/0.02 - 9*10^9*4*10^-9/0.02))

W = 0 J

Consider two point charges which are 4[cm] apart. q1 = + 4[nC] and q2 = - 4[nC]. a) Along the line that connects the two charges, where is the electric field du

Consider two point charges which are 4cm apart q1 4nC and

Solution

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