The hydroxide ion concentration in an aqueous solution at 25
The hydroxide ion concentration in an aqueous solution at 25°C is 2.7×10-2 M.
The hydronium ion concentration is_____________M.
The pH of this solution is _______________
The pOH is _______________
Solution
POH = - log[OH -] = -log[2.7*10^-2M]
= 1.568
PH + POH =14
Ph =14 - POH
=14- 1.568
PH =12.431
PH = -log[H3O+]
[H3O+] = antilog (-PH)
= antilog (-12.413)
=3.863*10^-13M
