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What does the following Scheme function do?

(define (y s lis)

(cond ((null? lis) \'() )

((equal? s (car lis)) lis)

(else (y s (cdr lis)))

))

Solution

What does the following Scheme function do?

(define (y s lis)

(cond ((null? lis) \'() )

((equal? s (car lis)) lis)

(else (y s (cdr lis)))

))

Answer:-

y returns the given list with leading elements removed up to but not including the first occurrence of the first given parameter.