Write fx 2x2 3x 5 in the form of ax h2 K Then find its

Write f(x) = 2x^2 - 3x + 5 in the form of a(x - h)^2 + K. Then find its Axis of symmetry & the maximum or minimum value & graph f(x).

Solution

f(x)=2x²-3x+5

f(x)= 2(x²-(3/2)x +9/4 -9/4)+5

f(x)= 2(x-(3/2))² +1/2

vertex(h,k)=(3/2,1/2)

Axis of symmetry is at x-3/2=0

x=3/2

Minimum value is 1/2 at x=3/2