Homework SourseIt is determine that it requires 150 footpounds of work in o
It is determine that it requires 15.0 foot-pounds of work in order to sketch a spring 1.25 feet beyond its natural length . How much work would be required to stretch the spring 9.00 inches beyond its natural length ? Express your answer in foot-pounds.
Please write some explanation too , please and thanks a loooot
Please write some explanation too , please and thanks a loooot
Solution
work=1/2*k*x^2 15=1/2*k*(1.25)^2 k=19.2 work required for stretching 9 inches is 1/2*k*(.75)^2 =1/2*19.2*(.75)^2 =5.4foot-pounds
