A pomegranate is thrown from ground level straight up into t

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 192 feet per second. Its height in feet at seconds is F(t)=-16t^2+192t . Find the time its hits the ground and the time it reaches its highest point.

Hits the ground when t =
Reaches highest point when t =
Maximum height =

Solution

At highest point, dF/dt = 0 -32t + 192 = 0 t = 6 s At time of hitting the ground, F = 0. -16t^2 + 192t = 0 t(-16t + 192) = 0 t = 0, 12 s Hence, time of hitting is 12 s.
A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 192 feet per second. Its height in feet at seconds is F(t)=-16t^2+1

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