For the given function find the equation of the secant line

For the given function, find the equation of the secant line through the points where x has the given values and the equation of the tangent line when x has the first value. y = f(x) = x2 + x; x = 1, x = 5 The equation of the secant line is y = (Simplify your answer. Type your answer in slope-intercept form.) The equation of the tangent line is y = (Simplify your answer. Type your answer in slope-intercept form.)

Solution

(f(5)-f(1))/(5-1) 30-2/4= 7 y= 7 x +b 2= 7 +b b=-5 y= 7 x-5 y\'= 2x +1 y\'(1)= 3 y=3x +b 2= 3 +b b-=1 y= 3x-1