10ml of 10 M boranetetrahydrofuran solution noleule of water

10ml of 1.0 M borane-tetrahydrofuran solution) noleule of water to create boric acid, how much water would it take to completely destroy your

Solution

no. of mole = molarity X volume of solution in liter

molarity of borane = 1.0 M

volume of borane = 4.0 ml = 0.004 liter

no. of mole of borane = 1.0 X 0.004 = 0.004 mole

According to reaction 1 molecule of borane react with 3 molecule of borane therefore to react with 0.004 mole of borane required water = 0.004 X3 = 0.012 mole

0.012 mole water required

molar mass of water = 18.01528 g/mol then 0.012 mole of water = 0.012 X 18.01528 = 0.216 gm

density of water = 1 gm/ml therefore 0.216 gm water = 0.216 ml

0.216 ml water required.