A negative charge q 280 times 106 C is located at the origi

A negative charge q = -2.80 times 10^-6 C is located at the origin and has velocity upsilon = (7.50 times 10^-1 m/s) i + ((-4.90) times 10^4 m/s) j. At this instant what is the magnetic field produced by this charge at the point x = 0.230 m, y = -0.250 m, z = 0? Enter the x, y, and z components of the magnetic field separated by commas.

Solution

magnetic field B = u₀/4pi * q(v X r)/r^3

v X r = [ i j k ]

[7.5*10^4 -4.9*10^4 0 ]

[0.23 -0.25 0]

= k (-1.875*10^4 + 1.127*10^4)

= -0.748 *10^4 k

r = sqrt(0.23^2 + 0.25^2) = 0.34 m

B = 4pi*10^-7 / 4pi * (-2.8*10^-6*k(-0.748*10^4)) / 0.34^3

B = 5.33*10^-8 k T

Bz = 5.33*10^-8 T