g to the following reaction how many moles of oxygen gas are

g to the following reaction, how many moles of oxygen gas are necessary to form 0.594 moles sulfur trioxide? sulfur dioxide (g) + oxygen (g)sulfur trioxide (g) moles oxygen gas

Solution

The balanced equation is

2 SO2 + O2 -----> 2 SO3

from the balanced equation we can say that

2 mole of SO3 is produced by 1 mole of O2 so

0.594 mole of SO3 will be produced by

= 0.594 mole of SO3 *(1 mole of O2 / 2 mole of SO3)

= 0.297 mole of O2

Therefore, the number of moles of oxygen required would be 0.297