The molality of potassium bromide KBr in an aqueous solution
The molality of potassium bromide, KBr, in an aqueous solution is 2.55 mol/kg. What is the MOLE FRACTION of potassium bromide in the solution?
Can someone please explain how to do this problem?
Solution
2.55 mol/kg
2.55 moles of KBr present
Moles of water = 1000.0 g / 18.0 g mol¯1 = 55.6 mol of H2O
MOLE FRACTION of potassium bromide = 2.55 / (2.55+ 55.6 ) = 0.0438
