The top of a 200 foot vertical tower is to be anchored by ca

The top of a 200 foot vertical tower is to be anchored by cables that make an angle of 60 degree with the ground. Please include units in your answers. All trig functions will be evaluated in degrees. How long must each cable be? How far from the base of the tower should anchors be placed? You have attempted this problem 0 times. You have unlimited attempts remaining.

Solution

Height of Tower, y =200 ft.
Angle, = 60°
Length of Cables = z
Distance from Tower = x

Sin = y / z
z = y / Sin
z = 200 / Sin 60
z = 200 / (sqrt3/2)
z = 400/sqrt(3)

Cable Length = 400/sqrt(3) ft.=230.94
x² = z² - y²
x² = (400/sqrt3)² - (200)²
x² = 160000/3 - 40000
x² = 40000/3
x = 40000/3
x = 115.47
Distance from Tower = 115.47ft.