Homework SourseFind the exact solutions in the interval 02pi sin2x cosx0Sol
Find the exact solutions in the interval [0,2pi]
sin(2x) -cos(x)=0
Solution
sin(2x) -cos(x)=0
=>2sin(x)cos(x) -cos(x)=0
=>(2sin(x) -1)cos(x)=0
=>(2sin(x) -1)=0 , cos(x)=0
=>sin(x) =1/2 , cos(x)=0
=>x=/6,5/6 ,x=/2,3/2
=>x=/6,/2,5/6 ,3/2
![Find the exact solutions in the interval [0,2pi] sin(2x) -cos(x)=0Solutionsin(2x) -cos(x)=0 =>2sin(x)cos(x) -cos(x)=0 =>(2sin(x) -1)cos(x)=0 =>(2sin(x)](/WebImages/44/find-the-exact-solutions-in-the-interval-02pi-sin2x-cosx0sol-1138819-1761610281-0.webp "Find the exact solutions in the interval [0,2pi] sin(2x) -cos(x)=0Solutionsin(2x) -cos(x)=0 =>2sin(x)cos(x) -cos(x)=0 =>(2sin(x) -1)cos(x)=0 =>(2sin(x)")
