A ball is thrown in the air from the top of a building Its h

A ball is thrown in the air from the top of a building. Its height, in meters above ground as a function of time, in seconds, is given by h(t) = -4.9t^2 + 19t + 14. How long does it take to reach maximum height? Round to the nearest hundredth of a second. seconds

Solution

h(t) = -4.9t^2 + 19t +14

amximum occurs at vertex of quadratic equation:

t = -b/2a = -(19/(2*-4.9) = 1.938 = 1.94 sec