In Exercise solve the given systems of equations algebraical

In Exercise, solve the given systems of equations algebraically. xy = 4 12x - 9y = 6

xy=4

x=4/y

Put this value of x in 2nd equation

12x-9y=6

12(4/y) -9y=6

48-9y^2 =6y

Divide entire equation by 3, we get

3y^2 +2y-16=0

3y^2 +8y-6y-16=0

y(3y+8)-2(3y+8)=0

Therefore, y-2=0 or 3y+8=0

This gives, y= 2, -8/3

Hence, x=4/y = 2, -3/2