MATH 140Pre Calculus OneaDay 18 The Law of Sines 1 Solve the

MATH 140-Pre Calculus One-a-Day 18 The Law of Sines 1. Solve the triangle ABC with LA-82, e- 200 feet, and LB-52 2. Solve the triangle where LC-8, a -120 feet, and c- 30 feet

Solution

<A=82 degree, <B=52 degree

<C=180-A-B=180-82-52=46 degree

sinC/c=sinA/a

sin46/200=sin 82/a

a=200 sin 82/sin 46

a=275.33

sinC/c=sinB/b

sin46/200=sin52/b

b=200 sin 52/sin 46

b=219.1