Ross Hopkins president of Hopkins Hospitality has developed

Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and predecessor relationships in the following table for building new motels. Time (weeks) Immediate Time (weeks) Immediate Activity PredecessorsActivity a b Predecessor(s) a m C, E 9 23 16 D, G, H I, J 12 21 C, E a) The expected (estimated) time for activity C is 12 weeks. (Round your response to two decimal places.) b) The variance for activity C is 1.78 weeks. (Round your response to two decimal places.) c) Based on the calculation of the estimated times, the critical path is A-B E F-H J-K d) The estimated time for the critical path is 42.67 weeks. (Round your response to two decimal places.) e) The activity variance along the critical path is 21.56 weeks. (Round your response to two decimal places.) ) The probability that Hopkins Hospitality will finish the project in 42 weeks or less isEnter as a probability and round your response to three decimal places)

Solution

The estimated time for the critical path = m = 42.67 weeks

The activity variance along the critical path = 21.56 weeks

Thus, standard deviation of activities along the critical path = S = Square root ( 21.56 ) = 4.643

Let Z value corresponding to the probability that Hopkins Hospital will finish the project in 42 weeks or less = Z1

Accordingly .

m + z1 x s = 42

42.67 + 4.643.Z1 = 42

Or, 4.643.Z1 = - 0.67

Or, Z1 = - 0.67/4.643 = - 0.14 ( rounded to 2 decimal places )

Corresponding value of probability for Z = - 0.14 is 0.44433

THE PROBABILITY THAT THE HOPKINS HOSPITALITY WILL FINISH THE PROJECT IN 42 WEEKS OR LESS 0.444

THE PROBABILITY THAT THE HOPKINS HOSPITALITY WILL FINISH THE PROJECT IN 42 WEEKS OR LESS 0.444