y x2 2x 2 The graph of a quadratic function is given Dete

y = -x^2 - 2x - 2 The graph of a quadratic function is given. Determine the function\'s equation. h(x) = (x - 2)^2 + 2 j(x) = (x - 2)^2 - 2 g(x) = (x + 2)^2 - 2 f(x) = (x + 2)^2 + 2 Find the range of the function. f(x) = x^2 - 8x + 26 [4, infinity] [-infinity, 4] [10, infinity] [-infinity, 0]

Solution

Answer 14)

y= -x^2-2x-2 = -(x+1)^2 -1

Thus, the vertex is (-1, -1) and parabola will open Down.

So correct option is B

Answer 15)

From graph, The vertex is at (-2,2), and parabola opens up, hence the equation is

y= (x +2)^2 +2

So correct option is D

Answer 16)

y=x^2-8x+26

=(x-4)^2 +10

So, the range is [10, infinity)

So correct option is C