Use the fundamental identities to find the value of the trig
     Use the fundamental identities to find the value of the trigonometric function. Find cot theta if csc theta = Squareroot 26/5 and theta is in quadrant I.  1/5  Squareroot 26  Squareroot 26/26  5 
  
  Solution
Solution:
Given; csc = 26 / 5
Since \"csc\" is defined as \"hypotenuse over opposite,\" draw a right triangle where sqrt(26) is the hypotenuse and 5 is the side opposite theta.
Then, since \"cot\" is defined as \"adjacent over opposite,\"
Using the Pythagorean theorem;
csc = r / y = 26 / 5
x^2 + y^2 = r^2,
so x^2 + 5^2 = (26)^2,
or x^2 = 1
 x = 1
cot = 1/5 Answer.

