Use the fundamental identities to find the value of the trig

Use the fundamental identities to find the value of the trigonometric function. Find cot theta if csc theta = Squareroot 26/5 and theta is in quadrant I. 1/5 Squareroot 26 Squareroot 26/26 5

Solution

Solution:

Given; csc = 26 / 5

Since \"csc\" is defined as \"hypotenuse over opposite,\" draw a right triangle where sqrt(26) is the hypotenuse and 5 is the side opposite theta.

Then, since \"cot\" is defined as \"adjacent over opposite,\"

Using the Pythagorean theorem;

csc = r / y = 26 / 5

x^2 + y^2 = r^2,

so x^2 + 5^2 = (26)^2,

or x^2 = 1
x = 1

cot = 1/5 Answer.

 Use the fundamental identities to find the value of the trigonometric function. Find cot theta if csc theta = Squareroot 26/5 and theta is in quadrant I. 1/5 S

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