Let fx x3ax2 bx where a b are constants For what values of

Let f(x) = x^3/ax^2 + bx, where a, b are constants. For what values of a, b is the graph of y = f(x) symmetric to the origin? (No work required) a. If a = 0 and b notequalto 0 b. If a notequalto 0 and b = 0 c. If a notequalto 0 and b notequalto 0 d. No such values of a, b exist

Solution

Solution:

Replace y with (-y) AND x with (-x). Simplify the equation. If the resulting equation is equivalent to the original equation then the graph is symmetrical about the origin.

Hence;

ax^2 -bx = ax^2 + bx

=> a 0 and b = 0

(Option-B)