raw ing irazketeh ot le sca le Solutiona 5 c 6 B 100 degr

raw ing i.r.azketeh ot le \'sca le)

a = 5

c = 6

B = 100 degree

Use The Law of Cosines to find side b = r first:

b² = a² + c² 2ac cosB = 5^2 + 6^2 - 2*5*6*cos100

b = r = 8.45

Now using

sin B/b = sin A/a

sinA = (a/b)*sinB = (5/8.45)*sin100 ======> A = 35.6 degree =

and

sin B/b = sin C/c

sinC = (c/b)*sinB = (6/8.45)*sin100 ======> C = 44.4 degree =

$raw ing i.r.azketeh ot le \'sca le) Solutiona = 5 c = 6 B = 100 degree Use The Law of Cosines to find side b = r first: b2 = a2 + c2 2ac cosB = 5^2 + 6^2 - 2*5$

raw ing irazketeh ot le sca le Solutiona 5 c 6 B 100 degr

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