me Fie Edit View History Bookmarks People Window Help 4 96 W

me Fie Edit View History Bookmarks People Window Help 4) 96% Wed 6:57 PM Tomas Martinez-Granata Take a Test federico murtagh Secure https://www.mathx.com/Student/Playermest aspx?test d 157384343&centerwin; yes MATH 203 AA INTERMEDIATE ALGEBRA-23841 federico murtagh 3/15/17 657 PM Test: Final Exam Online Section TIme Remaining: 02:06:30 Submit Tes This Question: 1 pt 28 of 35 P8 complete) v This Test: 35 pts possib initially, is being used in studies testing the enectiveness of drugs for preventing osteoporosis. The half life of calcium-41 is 100,000 years. lf5 grams of calcium-41 are present how long would it take until only 1 gram remains? It would take years until only 1 gram of calcium-41 remains. (Round the final answer to one decimal place as needed. Round all intermediate values to six decimal places as needed.) Enter your answer in the answer box. Graphing Functions: Examples page 3 of graph showing vertical asymptote x 3 Logarithmic some points 20-1

Solution

Dear Student Thank you for using Chegg !! Gvien Half Life of Calcium-41 = 100000 years Initial quantity (P0) = 5 grams Final quantity = 1 grams Since there is exponential decay in quantity of Calcium -41 Therefore quantity at any time t can be defined by P = P0exp(-kt) where k is rate of decay Half life means when P = P0/2 => P0/2 = P0 exp(-100000k) 0.5 = exp(-100000k) Taking natural log both sides -0.693147181 = -100000k k\'= = 6.93147E-06 Now time elapsed till t = 1 grams 1 = 5exp (-6.93e-6 * t) Taking natural log both sides -1.609437912 = -6.93e-6 * t years = 232192.8095 years Solution