maomEan leaming How many grams of solute are present in 455

maomEan leaming How many grams of solute are present in 455 mL of 0.170 M KBr? Number

Solution

Concentration of the KBr is 0.17 mol/L

1000 mL contains 0.17 mol solute

455 mL contains (0.17 mol* 455 mL )/ 1000 mL = 0.0773 moles of solute(KBr)

1 mol of KBr = 119 g
0.0773 mol of kBr = 0.0773 * 119 = 9.198 g

Grams of solute present in 445 mL of 0.170 M KBr = 9.198 g