PYTHON QUESTION I want to put else statement too If i put th

PYTHON QUESTION:

I want to put else statement too. If i put the \"Print (c) and b=input(\"enter a letter\"), then it will print things multiple times which i dont want. What do i need to do so that if userInput matches any letters of the word, it replaces all in c,else count=count-1, and asks userInput in loop. When 0,game over.

a apple b input (\"enter a letter court-5 while c! a for i in range (len(a) if b ali it wil replace all the position on c print (c) b input (\"enter a letter nog c pp suppose user input was \"p\" else: I can\'t put else statement there. It says invalid syntaxD count-count-i sir put(\"enter a letter b

Solution

You did well upto for loop declaration but the problem is in for loop :
You should check whether the input character is present in string then decrement count ,so it would be like this within the while loop :

while count>=0:
flag=0
if count==0:
print \'Game over\'
break
for i in range(len(a)):
if b==a[i]:
c[i]=b
flag=1
if flag==0:
count=count-1
b=input(\'enter a letter : \');
else:

print(c)
break