An aqueous solution of NaNO3 is 220 NaNO3 by mass The densit

An aqueous solution of NaNO3 is 22.0% NaNO3 by mass. The density of the solution is 1.127 g/mL. Calculate the molality, the molarity and the mole fraction of NaNO3

Solution

22 gm NaNO3 in 100 gm solution , solvent mas s= 78

moles of NaNO3 = 22/68.9 = 0.3193 , solution vol = 100/1.127 =88.73

Molarity = (0.3193/88.73) x1000 = 3.599 M,

molality = (0.319/78) x1000 = 4.09 m,

solvent moles = 78/18 =6.5,

mol fraction of NaNo3 = (0.3193)/(0.3193+6.5) = 0.0468