Homework SourseSuppose that a room containing 35m3 of air is free of carbon
Suppose that a room containing 35m3 of air is free of carbon monoxide. At time t = 0 cigarette
smoke containing 4% carbon monoxide is introduced at the rate of 2.8 10^-3m3/min, and
the well-circulated mixture is vented from the room at the same rate.
(a) Find a formula for the percentage of carbon monoxide in the room at time t.
(b) Extended exposure to air containing 0.012% carbon monoxide is considered dangerous.
How long will it take to reach this level?
smoke containing 4% carbon monoxide is introduced at the rate of 2.8 10^-3m3/min, and
the well-circulated mixture is vented from the room at the same rate.
(a) Find a formula for the percentage of carbon monoxide in the room at time t.
(b) Extended exposure to air containing 0.012% carbon monoxide is considered dangerous.
How long will it take to reach this level?
Solution
initial volume = 35m3 ;
cabon monooxide volume at any time \'t min\' = 2.8*10-3*t;
so total volume = 35+0.0028t m3;
amount of CO at any time t = 0.0028*4*t = 0.0112t ;
concentration of CO = amount/volume = 0.0112t /35+0.0028 t; --------->answer of a)
b.
0.012 =0.0112t/35+0.0028t;
0.42=0.0111664 t ;
t = 37.61 minutes-------------->Answer of b)
