Cons the vectors upsilon1 1 1 0 0 upsilon2 0 1 1 0 upsilon
Cons the vectors upsilon_1 = (1, 1, 0, 0), upsilon_2 = (0, 1, 1, 0), upsilon_3 = (0, 0, 1, 1) and upsilon_4 = (1, 0, 0, 1) in R^4. Determine if {upsilon_1, upsilon_2, upsilon_3, upsilon_4} are linearly independent or linearly dependent. If they are linearly dependent, find the nontrivial liner relation amongst them. b) Is span ({upsilon_1, upsilon_2, upsilon_3, upsilon_4}) = R^4. If so, explain why. If not, given an example of a vector omega that is not in span ({upsilon_1, upsilon_2, upsilon_3, upsilon_4}).

Solution
2. (a) Let A =
1
0
0
1
1
1
0
0
0
1
1
0
0
0
1
1
We will reduce A to its RREF as under:
Add -1 times the 1st row to the 2nd row
Add -1 times the 2nd row to the 3rd row
Add -1 times the 3rd row to the 4th row
Then the RREF of A is
1
0
0
1
0
1
0
-1
0
0
1
1
0
0
0
0
Apparently, v1 , v2 , v3, v4 are not linearly independent and v4 = v1 –v2 +v3 or, v1 –v2 +v3-v4 = 0
(b) It is apparent from the RREF of A that span{ v1 , v2 , v3, v4 } R4 as the last row of the RREF of A is a zero row. The vector, (0,0,0,1)T is not in span{ v1 , v2 , v3, v4 }.
| 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 0 | 0 | 1 | 1 |

