if 100 mL of 0030 M HCl solution is added to 100 mL of buffe
if 100. mL of 0.030 M HCl solution is added to 100. mL of buffer solution which is 0.10 M in NH3 and 0.1 M in Nh4Cl, what will be the pH of the new solution?
Solution
When 100 ml of 0.03M HCL is added , NH3 reacts with HCL to form NH4Cl .
amount of NH3 reacted = 0.03*100= 3 millimoles
Initially the soln contained 0.1*100=10 millimoles of NH3 and 10 millimoles of NH4Cl
now the soln contains 13 millimoles of NH4Cl and 7 millimoles of NH3
So according to nernest equation
pH = pKa+ log [NH3/[]NH4Cl]
=9.24 + log 7/13
=9.24-.27
=8.97
