C problem ask for help Write a program that asks the user to

C++ problem, ask for help

Write a program that asks the user to enter a character c1 and three float numbers x1, x2,

x3. The program should calculate and print the result depending upon the value of c1 as

follows:

If c1 = ‘X’: the result is the maximum of x1, x2, and x3

If c1 = ‘N’: the result is the minimum of x1, x2, and x3

If c1 = ‘V’: the result is the average of x1, x2, and x3

If c1 = ’S’ : stop

The program should keep asking the user to enter and process the data until the user

enters a character ‘S’ for c1.

Solution

#include <iostream>
#include <string> // std::string
#include <bitset>   

float findMax(float x,float y,float z);
float findMin(float x,float y,float z);
float findAvg(float x,float y,float z);

int main(int argc, char *argv[]) {

float x,y,z;
char c1;
while(1){
   std::cout << \"enter the values of c1,x,y,z separated by spaces\ \";
   std::cin >> c1;
   std::cin >> x;
   std::cin >> y;
   std::cin >> z;
   if(c1==\'X\'){
       std::cout << \"Maximum of x,y,z is \" << findMax(x,y,z) << \"\ \";
   }else if(c1==\'N\'){
       std::cout << \"Minimum of x,y,z is \" << findMin(x,y,z) << \"\ \";
   }else if(c1==\'V\'){
       std::cout << \"Average of x,y,z is \" << findAvg(x,y,z) << \"\ \";
   }else{
       break;
   }
}
  
}

//This function will find the maximum of three numbers

float findMax(float x,float y,float z){
   if(x>y){
       if(x>z){
           return x;
       }else{
           return z;
       }
      
   }else{
       if(y>z){
           return y;
       }else{
           return z;
       }
   }
}

//This function will find the minimum of three numbers

float findMin(float x,float y,float z){
   if(x<y){
       if(x<z){
           return x;
       }else{
           return z;
       }
      
   }else{
       if(y<z){
           return y;
       }else{
           return z;
       }
   }
}

//This function will find the average of three numbers

float findAvg(float x,float y,float z){
   float avg=(x+y+z)/3.0;
   return avg;
}