Calculate Kc for the following reaction at 25 C Mgs Pb2aq M
Calculate Kc for the following reaction at 25 °C:
Mg(s) + Pb^2+(aq) <---> Mg^2+(aq) + Pb(s)
begining by finding the value of E °cell
Solution
=2.25 V
so,
Eo=(0.059/2) *log(k)
or 2.25=(0.059/2) *log(k)
or k=1.867*10^76
| Mg2+(aq) + 2e-Â -> Mg(s) | -2.38 |
